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已知:C(s)+O2(g)═CO2(g)△H=-393.5kJ/mol,2H2(g)+O2(g)═2H2O(g)△H=-483.6kJ/mol,CO(g)+12O2(g)═CO2(g)△H=-283.0kJ/mol,则煤气化的主要反应的热化学方程式是C(s
题目详情
已知:C(s)+O2(g)═CO2(g)△H=-393.5kJ/mol,
2H2(g)+O2(g)═2H2O(g)△H=-483.6kJ/mol,
CO(g)+
O2(g)═CO2(g)△H=-283.0kJ/mol,
则煤气化的主要反应的热化学方程式是C(s)+H2O(g)═CO(g)+H2(g)△H=___.
2H2(g)+O2(g)═2H2O(g)△H=-483.6kJ/mol,
CO(g)+
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则煤气化的主要反应的热化学方程式是C(s)+H2O(g)═CO(g)+H2(g)△H=___.
▼优质解答
答案和解析
已知:①.C(s)+O2(g)═CO2(g)△H=-393.5kJ/mol,
②.2H2(g)+O2(g)═2H2O(g)△H=-483.6kJ/mol,
③.CO(g)+
O2(g)═CO2(g)△H=-283.0kJ/mol,
根据盖斯定律,①-②×
-③可得:C(s)+H2O(g)═CO(g)+H2(g),
故△H=-393.5kJ/mol-(-483.6kJ/mol)×
-(-283kJ/mol)=+131.3 kJ/mol,
故答案为:+131.3 kJ/mol.
②.2H2(g)+O2(g)═2H2O(g)△H=-483.6kJ/mol,
③.CO(g)+
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根据盖斯定律,①-②×
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故△H=-393.5kJ/mol-(-483.6kJ/mol)×
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故答案为:+131.3 kJ/mol.
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