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递等式计算64×81-81+81×37752-368+23276×992310÷[235-160÷(21+19)]125×48×2575×48+53×75
题目详情
递等式计算
64×81-81+81×37 | 752-368+232 | 76×99 |
2310÷[235-160÷(21+19)] | 125×48×25 | 75×48+53×75 |
▼优质解答
答案和解析
(1)64×81-81+81×37
=(64-1+37)×81
=100×81
=8100;
(2)752-368+232
=384+232
=616;
(3)76×99
=76×(100-1)
=76×100-76×1
=7600-76
=7524;
(4)2310÷[235-160÷(21+19)]
=2310÷[235-160÷40]
=2310÷[235-4]
=2310÷231
=10;
(5)125×48×25
=125×(8×6)×25
=(125×8)×(6×25)
=1000×150
=150000;
(6)75×48+53×75
=75×(48+53)
=75×101
=75×100+75
=7500+75
=7575.
=(64-1+37)×81
=100×81
=8100;
(2)752-368+232
=384+232
=616;
(3)76×99
=76×(100-1)
=76×100-76×1
=7600-76
=7524;
(4)2310÷[235-160÷(21+19)]
=2310÷[235-160÷40]
=2310÷[235-4]
=2310÷231
=10;
(5)125×48×25
=125×(8×6)×25
=(125×8)×(6×25)
=1000×150
=150000;
(6)75×48+53×75
=75×(48+53)
=75×101
=75×100+75
=7500+75
=7575.
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