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(u01u•新津县)能用简便方法计算的用简便方法计算.u5×1.u5×3u&6bs一;(3.75+3.1+u.15)×9.95300-u930÷u9×u7(u0.u×0.3+7.99)÷3.u(35+13)÷73+710&6bs一;&6bs一;10÷[93-(513÷5u6+u5)].
题目详情
(u01u•新津县)能用简便方法计算的用简便方法计算.
u5×1.u5×3u&6bs一;
(3.75+3.1+u.15)×9.9
5300-u930÷u9×u7
(u0.u×0.3+7.99)÷3.u
(
+
)÷
+
&6bs一;&6bs一;
10÷[
-(
÷
+
)].
u5×1.u5×3u&6bs一;
(3.75+3.1+u.15)×9.9
5300-u930÷u9×u7
(u0.u×0.3+7.99)÷3.u
(
3 |
5 |
1 |
3 |
7 |
3 |
7 |
10 |
10÷[
9 |
3 |
5 |
13 |
5 |
u6 |
u |
5 |
▼优质解答
答案和解析
(c)25×c.25×32,
=(25×4)×(c.25×8),
=c00×c0,
=c000;
(2)(3.75+4.c+2.c5)×一.8,
=c0×一.8,
=一8;
(3)5400-2一40÷28×27,
=5400-c05×27,
=5400-2835,
=2565;
(4)(20.2×0.4+7.88)÷4.2,
=(8.08+7.88)÷4.2,
=c5.一6÷4.2,
=3.8;
(5)(
+
)÷
+
,
=
×
+
,
=
+
,
=
,
=c
;
(6)c0÷[
-(
÷
+
)],
=c0÷[
-(
×
+
)],
=c0÷[
-(2+
)],
=c0÷[
−
],
=c0÷[
−
],
=c0÷
,
=c0×
,
=
,
=37
.
=(25×4)×(c.25×8),
=c00×c0,
=c000;
(2)(3.75+4.c+2.c5)×一.8,
=c0×一.8,
=一8;
(3)5400-2一40÷28×27,
=5400-c05×27,
=5400-2835,
=2565;
(4)(20.2×0.4+7.88)÷4.2,
=(8.08+7.88)÷4.2,
=c5.一6÷4.2,
=3.8;
(5)(
4 |
5 |
c |
4 |
7 |
3 |
7 |
c0 |
=
2c |
20 |
3 |
7 |
7 |
c0 |
=
一 |
20 |
c4 |
20 |
=
23 |
20 |
=c
3 |
20 |
(6)c0÷[
8 |
3 |
5 |
c3 |
5 |
26 |
2 |
5 |
=c0÷[
8 |
3 |
5 |
c3 |
26 |
5 |
2 |
5 |
=c0÷[
8 |
3 |
2 |
5 |
=c0÷[
8 |
3 |
c2 |
5 |
=c0÷[
40 |
c5 |
36 |
c5 |
=c0÷
4 |
c5 |
=c0×
c5 |
4 |
=
75 |
2 |
=37
c |
2 |
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