C#中如何生成一个18位的随机数,

Question

C#中如何生成一个18位的随机数,

Answer 1

//len 为长度
public String get(int len)
{
try
{
String str = "";
while (str.Length < len)
{
raStr += ra.Next();
}
return raStr.Substring(0, len);
}
catch (Exception e)
{
return "";
}
}