长度为34nm的B-DNA双螺旋片段中可以形成的氢键数量最少为多少长度为34nm的B-DNA双螺旋片段中可以形成的氢键数量最少为多少？最多为多少

Question

长度为34 nm的B-DNA双螺旋片段中可以形成的氢键数量最少为多少
长度为34 nm的B-DNA双螺旋片段中可以形成的氢键数量最少为多少？最多为多少

Answer 1

200.
The DNA double helix contains exactly 10 nucleotide pairs per turn and each turn adds 3.4 nm to the overall length of the duplex.
34 nm --> 10 turns --> 10x10=100 nucleotides --> A and T make 2 hydrogen bonds,C and G makes 3 -->minimum number of hydrogen bond 100x2=200