欲配制1L含0.5m0LNaCl、0.16m0LKCl、0.24m0LK2S04的混合溶液,现用硫酸钠代替硫酸钾进行配制,则所需NaCl...欲配制1L含0.5m0LNaCl、0.16m0LKCl、0.24m0LK2S04的混合溶液,现用硫酸钠代替硫酸钾进行配制,则所需NaC

Question

欲配制1L含0.5m0LNaCl、0.16m0LKCl、0.24m0LK2S04的混合溶液,现用硫酸钠代替硫酸钾进行配制,则所需NaCl...
欲配制1L含0.5m0LNaCl、0.16m0LKCl、0.24m0LK2S04的混合溶液,现用硫酸钠代替硫酸钾进行配制,则所需NaCl、KCl、Na2S04三种固体物质的量分别为多少

Answer 1

n（SO4^2-)=n(K2S04)=0.24mol
n(Na2SO4)=n（SO4^2-)=0.24mol
n(Na^+)=2n(Na2SO4)=2*0.24mol=0.48mol
n(NaCl)=0.5mol-0.48mol=0.02mol
n(KCl)=0.16mol+0.24mol*2=0.64mol
需NaCl、KCl、Na2S04三种固体物质的量分别为0.02mol、0.64mol、0.24mol