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写出下列化学反应方程式:(1)实验室制溴苯C6H6+Br2FeBr3C6H5Br+HBrC6H6+Br2FeBr3C6H5Br+HBr;(2)乙醇与钠反应;(3)工业生产聚乙烯;(4)乙醇的催化氧化2C2H5OH+O2铜或银△2CH3CHO+2H2O2C2H5OH

题目详情
写出下列化学反应方程式:
(1)实验室制溴苯
C6H6+Br2
FeBr3
C6H5Br+HBr
C6H6+Br2
FeBr3
C6H5Br+HBr

(2)乙醇与钠反应______;
(3)工业生产聚乙烯______;
(4)乙醇的催化氧化
2C2H5OH+O2
铜或银
2CH3CHO+2H2O
2C2H5OH+O2
铜或银
2CH3CHO+2H2O

(5)巴豆酸CH3-CH=CH-COOH与甲醇的酯化反应
CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O
CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O

C6H6+Br2
FeBr3
C6H5Br+HBr
662
FeBr3
C6H5Br+HBr
FeBr3
FeBr3FeBr3r3r33
65
C6H6+Br2
FeBr3
C6H5Br+HBr
662
FeBr3
C6H5Br+HBr
FeBr3
FeBr3FeBr3r3r33
65


2C2H5OH+O2
铜或银
2CH3CHO+2H2O
252
铜或银
2CH3CHO+2H2O
铜或银
铜或银铜或银
△△32
2C2H5OH+O2
铜或银
2CH3CHO+2H2O
252
铜或银
2CH3CHO+2H2O
铜或银
铜或银铜或银
△△32
3
CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O
33
浓硫酸
CH3-CH=CH-COOCH3+H2O
浓硫酸
浓硫酸浓硫酸
△△332
CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O
33
浓硫酸
CH3-CH=CH-COOCH3+H2O
浓硫酸
浓硫酸浓硫酸
△△332
▼优质解答
答案和解析
(1)苯和纯溴在三溴化铁催化剂作用下,苯环上一个氢原子发生取代反应生成溴苯和溴化氢,C66H66+Br22
FeBr3
C6H5Br+HBr,
故答案为:C6H6+Br2
FeBr3
C6H5Br+HBr;
(2)羟基可与金属钠反应放出氢气,钠和乙醇反应生成乙醇钠和氢气,反应方程式为:2Na+2C2H5OH→H2↑+2C2H5ONa,
故答案为:2CH3CH2OH+2Na→2CH3CH2ONa+H2↑;
(3)乙烯分子含有双键,自身反应双键变单键,断开的单键相连接形成高分子化合物,生成聚乙烯:
故答案为:
(4)乙醇在铜或银等催化剂存在下被氧气氧化生成乙醛和水,反应为:2C2H5OH+O2
铜或银
2CH3CHO+2H2O,
故答案为:2C2H5OH+O2
铜或银
2CH3CHO+2H2O;
(5)巴豆酸CH3-CH=CH-COOH与甲醇在浓硫酸作用下反应,酸脱羟基醇脱氢,反应为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O,
故答案为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O.
FeBr3
FeBr3FeBr3FeBr33
C66H55Br+HBr,
故答案为:C66H66+Br22
FeBr3
C6H5Br+HBr;
(2)羟基可与金属钠反应放出氢气,钠和乙醇反应生成乙醇钠和氢气,反应方程式为:2Na+2C2H5OH→H2↑+2C2H5ONa,
故答案为:2CH3CH2OH+2Na→2CH3CH2ONa+H2↑;
(3)乙烯分子含有双键,自身反应双键变单键,断开的单键相连接形成高分子化合物,生成聚乙烯:
故答案为:
(4)乙醇在铜或银等催化剂存在下被氧气氧化生成乙醛和水,反应为:2C2H5OH+O2
铜或银
2CH3CHO+2H2O,
故答案为:2C2H5OH+O2
铜或银
2CH3CHO+2H2O;
(5)巴豆酸CH3-CH=CH-COOH与甲醇在浓硫酸作用下反应,酸脱羟基醇脱氢,反应为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O,
故答案为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O.
FeBr3
FeBr3FeBr3FeBr33
C66H55Br+HBr;
(2)羟基可与金属钠反应放出氢气,钠和乙醇反应生成乙醇钠和氢气,反应方程式为:2Na+2C22H55OH→H22↑+2C22H55ONa,
故答案为:2CH33CH22OH+2Na→2CH33CH22ONa+H22↑;
(3)乙烯分子含有双键,自身反应双键变单键,断开的单键相连接形成高分子化合物,生成聚乙烯:
故答案为:
(4)乙醇在铜或银等催化剂存在下被氧气氧化生成乙醛和水,反应为:2C22H55OH+O22
铜或银
2CH3CHO+2H2O,
故答案为:2C2H5OH+O2
铜或银
2CH3CHO+2H2O;
(5)巴豆酸CH3-CH=CH-COOH与甲醇在浓硫酸作用下反应,酸脱羟基醇脱氢,反应为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O,
故答案为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O.
铜或银
铜或银铜或银铜或银
△△△2CH33CHO+2H22O,
故答案为:2C22H55OH+O22
铜或银
2CH3CHO+2H2O;
(5)巴豆酸CH3-CH=CH-COOH与甲醇在浓硫酸作用下反应,酸脱羟基醇脱氢,反应为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O,
故答案为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O.
铜或银
铜或银铜或银铜或银
△△△2CH33CHO+2H22O;
(5)巴豆酸CH33-CH=CH-COOH与甲醇在浓硫酸作用下反应,酸脱羟基醇脱氢,反应为:CH33-CH=CH-COOH+CH33OH
浓硫酸
CH3-CH=CH-COOCH3+H2O,
故答案为:CH3-CH=CH-COOH+CH3OH
浓硫酸
CH3-CH=CH-COOCH3+H2O.
浓硫酸
浓硫酸浓硫酸浓硫酸
△△△CH33-CH=CH-COOCH33+H22O,
故答案为:CH33-CH=CH-COOH+CH33OH
浓硫酸
CH3-CH=CH-COOCH3+H2O.
浓硫酸
浓硫酸浓硫酸浓硫酸
△△△CH33-CH=CH-COOCH33+H22O.