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cos12°-cos24°-cos48°+cos84°

题目详情
cos12°-cos24°-cos48°+cos84°
▼优质解答
答案和解析
cos12°-cos24°-cos48°+cos84°
=cos12°+cos84°-cos24°-cos48°
=2cos48°cos36°-2cos36°cos12°
=2cos36°(cos48°-cos12°)
=-2cos36°2sin30°sin18°
=-2cos36°sin18°
=-2cos36°cos72°
=-2(√5+1)/4*[2(√5+1)^2/16-1]
=-1/2