考察下列一组不等式：23+53＞22×5+2×5224+54＞23×5+2×53252+552＞22×512+212×52…，将上述不等式在左右两端视为两项和的情况下加以推广，使以上的不等式成为推广不等式的特例，则推广的不等式

Question

23+53＞22×5+2×52

24+54＞23×5+2×53

2(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52

…

，将上述不等式在左右两端视为两项和的情况下加以推广，使以上的不等式成为推广不等式的特例，则推广的不等式为______．

23+53＞22×5+2×52

24+54＞23×5+2×53

2(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52

…

23+53＞22×5+2×52

24+54＞23×5+2×53

2(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52

…

23+53＞22×5+2×52

24+54＞23×5+2×53

2(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52

…

23+53＞22×5+2×52

24+54＞23×5+2×53

2(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52

…

23+53＞22×5+2×5223+53＞22×5+2×5223+53＞22×5+2×5223+53＞22×5+2×523+53＞22×5+2×5253＞22×5+2×5253＞22×5+2×523＞22×5+2×5222×5+2×5222×5+2×522×5+2×525252224+54＞23×5+2×5324+54＞23×5+2×5324+54＞23×5+2×5324+54＞23×5+2×534+54＞23×5+2×5354＞23×5+2×5354＞23×5+2×534＞23×5+2×5323×5+2×5323×5+2×533×5+2×53535332(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×522(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×522(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×522(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52(5)/(2)+5(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52(5)/(2)55225(5)/(2)＞22×5(1)/(2)+2(1)/(2)×525(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52(5)/(2)＞22×5(1)/(2)+2(1)/(2)×52(5)/(2)552222×5(1)/(2)+2(1)/(2)×5222×5(1)/(2)+2(1)/(2)×522×5(1)/(2)+2(1)/(2)×525(1)/(2)+2(1)/(2)×525(1)/(2)+2(1)/(2)×52(1)/(2)+2(1)/(2)×52(1)/(2)11222(1)/(2)×522(1)/(2)×52(1)/(2)×52(1)/(2)112252522……

Answer 1

由不等式：23+53＞22×5+2×5224+54＞23×5+2×53252+552＞22×512+212×52…我们分析不等号两端式子结构的特点，及指数之间的关系不难推断：am+n+bm+n＞ambn+anbm（a，b，m，n＞0，且a≠b）故选Am+n+bm+n＞ambn+anb...