计算(1+1/2048)+(2+1/1024)+(4+1/512)+...(512+1/4)+(1024+1/2)n+1/b=n又1分之b计算1/2+3/4+5/8+7/16+.+199/2^100n+1/b=n又1分之b不是题..199/2^100是199/2的100次方

Answer 1

1)原式=(1+2+4+...+1024)+(1/2048+1/512+...+1/2)
=(1+2+4+...+1024+1-1))+(1/2048+1/512+...+1/2+1/1204-1/1024)
=(2*1024-1)+(1-1/1024)
=2047+1023/1024
2)不知道.