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用递等式计算.(能简算的要简算)35×(512÷34)56+712÷123.7×99+3.737+511+47+611360÷15+2.5×1623÷〔1-(13-14)〕
题目详情
用递等式计算. (能简算的要简算)
|
| 3.7×99+3.7 | ||||||||||||||
| 360÷15+2.5×16 |
|
用递等式计算. (能简算的要简算)
|
| 3.7×99+3.7 | ||||||||||||||
| 360÷15+2.5×16 |
|
3 |
5 |
5 |
12 |
3 |
4 |
5 |
6 |
7 |
12 |
1 |
2 |
3 |
5 |
5 |
12 |
3 |
4 |
3 |
5 |
5 |
12 |
3 |
4 |
3 |
5 |
5 |
12 |
3 |
4 |
5 |
12 |
3 |
4 |
3 |
4 |
5 |
6 |
7 |
12 |
1 |
2 |
5 |
6 |
7 |
12 |
1 |
2 |
5 |
6 |
7 |
12 |
1 |
2 |
7 |
12 |
1 |
2 |
1 |
2 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
2 |
3 |
1 |
3 |
1 |
4 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
5 |
11 |
4 |
7 |
6 |
11 |
4 |
7 |
6 |
11 |
6 |
11 |
2 |
3 |
1 |
3 |
1 |
4 |
2 |
3 |
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3 |
1 |
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1 |
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1 |
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4 |
▼优质解答
答案和解析
(1)
×(
÷
),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 35 5 5×(
÷
),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 512 12 12÷
),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 34 4 4),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 35 5 5×
5 5 59 9 9,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 13 3 3;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 56 6 6+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
7 7 712 12 12÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 12 2 2,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 56 6 6+
7 7 76 6 6,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 37 7 7+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 511 11 11+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
4 4 47 7 7+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
6 6 611 11 11,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 37 7 7+
4 4 47 7 7)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 511 11 11+
6 6 611 11 11),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
2 2 23 3 3÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 13 3 3-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 14 4 4)〕,
=
÷〔1-
〕,
=
÷
,
=
.
2 2 23 3 3÷〔1-
〕,
=
÷
,
=
.
1 1 112 12 12〕,
=
÷
,
=
.
2 2 23 3 3÷
,
=
.
11 11 1112 12 12,
=
.
8 8 811 11 11.
3 |
5 |
5 |
12 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
5 |
5 |
12 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
12 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
2 |
3 |
11 |
12 |
=
8 |
11 |
11 |
12 |
=
8 |
11 |
8 |
11 |
看了 用递等式计算.(能简算的要简...的网友还看了以下:
观察下列等式:1^3=1^2,1^3+2^3=3^2,1^3+2^3+3^3=6^2,1^3+2^ 2020-05-15 …
1+2+3+n=2分之1n(n+1),n是正整数,研究1*2+2*3+你(n+1),观察1*2=3 2020-05-20 …
1^2/1^3-(1^2+2^2)/(1^3+2^3)+.-(1^2+2^2+...+80^2)/ 2020-06-02 …
1+1/1*3+1/2*3+1/2*5+1/3*5+1/3*7+1/4*7+1/4*9原式=2*[ 2020-06-11 …
观察各式3*1=3,3*3=9,3*3*3=27,3*3*3*3=81...观察各式3*1=3,3 2020-07-19 …
1×2+2×3+3×4+4×5+…+n(n+1)=(n为自然数).因为:1×2=1/3×1×2×3 2020-07-21 …
一元一次不等式组(1){x+2≥0,3x-1/2<2x+1/3(2){2/5(3-x)+2<-2, 2020-07-29 …
虚数化简1/4*(-4+4*i*3^(1/2))^(1/3)+1/(-4+4*i*3^(1/2)) 2020-07-30 …
几道简便计算数学题[(1-3/1)的2次-(-1又3分之2)÷(-1又8分之7)]×(-1又2分之1 2020-11-15 …
等比数列1,3∧1/2,3∧3/2的通项公式是什么?答案写的是3∧(n-1)/2但是第三项3∧3等比 2021-01-27 …