早教吧作业答案频道 -->其他-->
（2012•勐海县）脱式计算，注意能简算的要简算．4.8×2.35+2.35×5.26÷[（1112-23）÷34]35×12+3÷530.5÷[（12+34）×0.2]（0.8-12）÷（1-47）2012×20102011
题目详情
（2012•勐海县）
脱式计算，注意能简算的要简算．
4.8×2.35+2.35×5.2
6÷[（
-
）÷
]脱式计算，注意能简算的要简算．
4.8×2.35+2.35×5.2
6÷[（
-
）÷
]
-
）÷
]
11 11 12 12
）÷
]
2 2 3 3
]
3 3 4 4
×12+3÷
0.5÷[（
+
）×0.2]
×12+3÷
×12+3÷
3 3 5 5
5 5 3 3 0.5÷[（
+
）×0.2]
+
）×0.2]
1 1 2 2
）×0.2]
3 3 4 4 （0.8-
）÷（1-
） 2012×
（0.8-
）÷（1-
）
）÷（1-
）
1 1 2 2
）
4 4 7 7 2012×
2010 2010 2011 2011
| 脱式计算，注意能简算的要简算． 4.8×2.35+2.35×5.2 | 6÷[（
| ||||||||
| 0.5÷[（
| ||||||||
（0.8-
| 2012×
|
| 脱式计算，注意能简算的要简算． 4.8×2.35+2.35×5.2 | 6÷[（
| ||||||||
| 0.5÷[（
| ||||||||
（0.8-
| 2012×
|
4.8×2.35+2.35×5.2
6÷[（
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
4.8×2.35+2.35×5.2
6÷[（
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
| 2 |
| 3 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 5 |
| 5 |
| 3 |
| 1 |
| 2 |
| 3 |
| 4 |
| 3 |
| 5 |
| 5 |
| 3 |
| 3 |
| 5 |
| 5 |
| 3 |
| 3 |
| 5 |
| 5 |
| 3 |
| 5 |
| 3 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 2 |
| 4 |
| 7 |
| 2010 |
| 2011 |
| 1 |
| 2 |
| 4 |
| 7 |
| 1 |
| 2 |
| 4 |
| 7 |
| 1 |
| 2 |
| 4 |
| 7 |
| 4 |
| 7 |
| 2010 |
| 2011 |
| 2010 |
| 2011 |
| 2010 |
| 2011 |
▼优质解答
答案和解析
（1）4.8×2.35+2.35×5.2
=（4.8+5.2）×2.35
=10×2.35
=23.5；
（2）6÷[（
-
）÷
]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
11 11 1112 12 12-
）÷
]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
2 2 23 3 3）÷
]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 34 4 4]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 14 4 4÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 34 4 4]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 13 3 3
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
5 5 53 3 3
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 12 2 2+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 34 4 4）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
5 5 54 4 4×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 14 4 4
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 12 2 2）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
4 4 47 7 7）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 310 10 10÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 37 7 7
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
7 7 710 10 10；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011
=2011×
+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011
=2010+
=2010
．
2010 2010 20102011 2011 2011
=2010
．
2010 2010 20102011 2011 2011．
=（4.8+5.2）×2.35
=10×2.35
=23.5；
（2）6÷[（
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2 |
| 3 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
看了 （2012•勐海县）脱式计算...的网友还看了以下：
Matlab符号计算问题我用Matlab计算0.4-0.3-0.1,使用符号计算,sym（‘0.4 2020-05-16 …
简算0.16×9.85+264×0.0985+72×0.985=?简算4800÷12.5÷2.5÷ 2020-06-11 …
0.125×72简便计算3.2×2.5简便计算0.93×99简便计算70.1×9.9简便计算0.9 2020-07-17 …
一、口算:0.1×208=7.2÷36=4.8÷16=1.3×50=0.5×20=0.81÷0.0 2020-07-19 …
按照找出的规律计算0.1+0.3+0.5+0.7+...+201.1+201.3等于多少?观察下面 2020-07-26 …
关于指数是分数0.8的0.6次方怎么计算的啊?如果是算0.512开5次方根怎么计算?用计算器怎么算 2020-07-30 …
并联串联的概率计算元件1,2并联,元件3,4串联的线路,元件可以工作的概率都是0.9,求系统可以工作 2020-11-03 …
为何0不可以做除数0×0=0.不是么.为何积不能除以因数?也不是0÷0么?为何不可逆运算?0÷0≠0 2020-11-15 …
计算0.32-2/7+0.77-5/7的最好方法是()a.按顺序计算b.运用加法结合律c.运用分配律 2020-11-27 …
比特运算0+0=0,0+1=1+0=1,1+1=10求解10+10=?怎么算的比特运算0+0=0,0 2020-11-29 …