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（2012•勐海县）脱式计算，注意能简算的要简算．4.8×2.35+2.35×5.26÷[（1112-23）÷34]35×12+3÷530.5÷[（12+34）×0.2]（0.8-12）÷（1-47）2012×20102011
题目详情
（2012•勐海县）
脱式计算，注意能简算的要简算．
4.8×2.35+2.35×5.2
6÷[（
-
）÷
]脱式计算，注意能简算的要简算．
4.8×2.35+2.35×5.2
6÷[（
-
）÷
]
-
）÷
]
11 11 12 12
）÷
]
2 2 3 3
]
3 3 4 4
×12+3÷
0.5÷[（
+
）×0.2]
×12+3÷
×12+3÷
3 3 5 5
5 5 3 3 0.5÷[（
+
）×0.2]
+
）×0.2]
1 1 2 2
）×0.2]
3 3 4 4 （0.8-
）÷（1-
） 2012×
（0.8-
）÷（1-
）
）÷（1-
）
1 1 2 2
）
4 4 7 7 2012×
2010 2010 2011 2011
| 脱式计算，注意能简算的要简算． 4.8×2.35+2.35×5.2 | 6÷[（
| ||||||||
| 0.5÷[（
| ||||||||
（0.8-
| 2012×
|
| 脱式计算，注意能简算的要简算． 4.8×2.35+2.35×5.2 | 6÷[（
| ||||||||
| 0.5÷[（
| ||||||||
（0.8-
| 2012×
|
4.8×2.35+2.35×5.2
6÷[（
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
4.8×2.35+2.35×5.2
6÷[（
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
| 11 |
| 12 |
| 2 |
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| 3 |
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| 2 |
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| 3 |
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| 3 |
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| 3 |
| 5 |
| 5 |
| 3 |
| 1 |
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| 3 |
| 5 |
| 5 |
| 3 |
| 3 |
| 5 |
| 5 |
| 3 |
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| 5 |
| 3 |
| 1 |
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| 1 |
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| 4 |
| 1 |
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| 3 |
| 4 |
| 1 |
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| 7 |
| 2010 |
| 2011 |
| 1 |
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| 4 |
| 7 |
| 1 |
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| 4 |
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| 1 |
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| 2010 |
| 2011 |
▼优质解答
答案和解析
（1）4.8×2.35+2.35×5.2
=（4.8+5.2）×2.35
=10×2.35
=23.5；
（2）6÷[（
-
）÷
]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
11 11 1112 12 12-
）÷
]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
2 2 23 3 3）÷
]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 34 4 4]
=6÷[
÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 14 4 4÷
]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 34 4 4]
=6÷
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 13 3 3
=18；
（3）
×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×12+3÷
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
5 5 53 3 3
=
×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×12+3×
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5
=
×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×（12+3）
=
×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 35 5 5×15
=9；
（4）0.5÷[（
+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 12 2 2+
）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 34 4 4）×0.2]
=0.5÷[
×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
5 5 54 4 4×0.2]
=0.5÷
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 14 4 4
=2；
（5）（0.8-
）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
1 1 12 2 2）÷（1-
）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
4 4 47 7 7）
=
÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 310 10 10÷
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
3 3 37 7 7
=
；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
7 7 710 10 10；
（6）2012×
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011
=（2011+1）×
=2011×
+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011
=2011×
+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011+1×
=2010+
=2010
．
2010 2010 20102011 2011 2011
=2010+
=2010
．
2010 2010 20102011 2011 2011
=2010
．
2010 2010 20102011 2011 2011．
=（4.8+5.2）×2.35
=10×2.35
=23.5；
（2）6÷[（
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 11 |
| 12 |
| 2 |
| 3 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2 |
| 3 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 4 |
=6÷[
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 4 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 4 |
=6÷
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 3 |
=18；
（3）
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 5 |
| 3 |
=
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
=
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 5 |
=9；
（4）0.5÷[（
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 2 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 4 |
=0.5÷[
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 5 |
| 4 |
=0.5÷
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 4 |
=2；
（5）（0.8-
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 1 |
| 2 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 4 |
| 7 |
=
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 10 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 3 |
| 7 |
=
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 7 |
| 10 |
（6）2012×
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=（2011+1）×
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2011×
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010+
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
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| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
=2010
| 2010 |
| 2011 |
| 2010 |
| 2011 |
看了 （2012•勐海县）脱式计算...的网友还看了以下：
脱式计算（能简便的要简算）（1）580+522÷29×15；（2）14.87-3.34-5.66； 2020-04-07 …
简便计算×34.5×8.23-34.5+2.77×34.519.98×37-199.8×1.9+1 2020-04-07 …
计算：34.5×8.23-34.5+2.77×34.5=． 2020-07-06 …
长凳可坐5人，短凳可坐3人，全班有34人．（1）如果要使搬的凳子尽量少，应怎样搬呢？（2）如果要使 2020-07-14 …
脱式计算（能简算的要简算）．72.8÷5.6+1.4958.1-29.7÷330.94-5.09- 2020-07-17 …
一个样本含有20个数据：35,31,33,35,37,39,35,38,40,39,36,34,3 2020-07-30 …
一个样本含有20个数据：35，31，35，37，39，35，38，40，39，33，34，35，37 2020-11-06 …
求1,2,3,5,8,13,21,34…的通式也可以是1,1,2,3,5,8,13,21,34… 2020-11-07 …
34.5×0.26，0.345×2.6，34.5×2.6三个算式中得数最大的是，得数最小的是． 2020-11-18 …
找出规律,写出第四行、第五行相等的算式.1+2=34+5+6=7+88+10+11+12=1找出规律 2020-12-15 …