早教吧作业答案频道 -->数学-->
（2012•北京模拟）（1）3015-3015÷15（2）1314-1315+114-215（3）（1-14+13）÷26（4）6.3÷[（417-0.07×50）÷127]．
题目详情
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 2 |
| 15 |
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 1 |
| 3 |
| 1 |
| 7 |
| 2 |
| 7 |
| 1 |
| 7 |
| 2 |
| 7 |
| 2 |
| 7 |
▼优质解答
答案和解析
（1）3015-3015÷15，
=3015-201，
=3015-200-1，
=2815-1，
=2814；
（2）
-
+
-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1314 14 14-
+
-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1315 15 15+
-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 114 14 14-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
2 2 215 15 15，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1314 14 14+
1 1 114 14 14）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1315 15 15+
2 2 215 15 15），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 14 4 4+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 13 3 3）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
3 3 34 4 4+
1 1 13 3 3）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1312 12 12÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 124 24 24；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 17 7 7-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
2 2 27 7 7]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 17 7 7-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
2 2 27 7 7]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
9 9 914 14 14÷1
2 2 27 7 7]，
=6.3÷
，
=12.6．
1 1 12 2 2，
=12.6．
=3015-201，
=3015-200-1，
=2815-1，
=2814；
（2）
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 2 |
=12.6．
看了 （2012•北京模拟）（1）...的网友还看了以下：
计算：（1）（-12+13-14-15）×（-20）（2）-56×（12-225-0.6）（3）（ 2020-04-07 …
简便计算53×54+54×16+69×25+21×69（3214-2213）×214×21356× 2020-04-07 …
口算．7200÷8=300÷6=2100+500=0÷72=126÷3=215÷5=29×0=91 2020-05-17 …
解方程．6X+18=483（X+2.1）=10.5X+4.8=7.215×（x+0.6）=185. 2020-07-18 …
把215×3改写成加法算式是215+215+215．215+215+215．． 2020-07-19 …
用简便方法计算．（1）3.99×2.45（2）5.6÷1.6（3）1.25×32+215×9.76 2020-07-19 …
若平面薄片D由曲线y=1−x2（0≤x≤1）与坐标轴围成，面密度为1，则该平面薄片对直线l：x+y 2020-07-19 …
计算下面各题（能简算的要简算）．①4×0.8×2.5×12.5②215÷[1-（15+13）]③（ 2020-07-19 …
把下列各数填在相应的集合里：+5，-12，-20，0，0.74，-115，+3，-9.8，241， 2020-07-26 …
计算下面各题（能简算的要简算）②515+223-415①1÷(1+34)④213×12.5×67× 2020-07-29 …