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以下算式怎样简便怎样算(写出步奏)谢谢!2005×12/20044-(5/7+1/3)-2/7(3又12分之5-1又7分之3)-(1又7分之4-1又12分之7)38×1/4+0.25×41又2分之一+20.5×1/4(1/12+1/15)×12×15(7/13×5/11)×13×1142×9
题目详情
▼优质解答
答案和解析
NO1:
2005×12/2004
=(2004+1)*12/2004
=2004*12/2004+12/2004
=12+3/501
NO2:
4-(5/7+1/3)-2/7
=4-5/7-1/3-2/7
=4-(5/7+2/7)-1/3=4-1-1/3
=2 2/3
NO3:
(3又12分之5-1又7分之3)-(1又7分之4-1又12分之7)
=3 5/12-1 3/7-1 4/7+1 7/12
=(3 5/12+1 7/12)-(1 3/7+1 4/7)
=5-3
=2
NO:4
38×1/4+0.25×41又2分之一+20.5×1/4
=38/0.25+0.25*41.5+20.5*0.25
=(38+41.5+20.5)*0.25
=80*0.25
=20
NO5:
(1/12+1/15)×12×15
=(1/12×12×15)+(1/15×12×15)
=15+12
=27
NO6:
(7/13×5/11)×13×11
=(7/13×13×11)*(5/11×13×11)
=77*65
=70*65+7*65
=4550+455
=5005
NO7 :
42×9/24-3/8
=42*3/8-3/8
=41*3/8
=40*3/8+3/8
=15+3/8
NO:8
三十九又五分之二÷13
=(39 2/5)/13
=39/13+(2/5)/13
=3+2/65
2005×12/2004
=(2004+1)*12/2004
=2004*12/2004+12/2004
=12+3/501
NO2:
4-(5/7+1/3)-2/7
=4-5/7-1/3-2/7
=4-(5/7+2/7)-1/3=4-1-1/3
=2 2/3
NO3:
(3又12分之5-1又7分之3)-(1又7分之4-1又12分之7)
=3 5/12-1 3/7-1 4/7+1 7/12
=(3 5/12+1 7/12)-(1 3/7+1 4/7)
=5-3
=2
NO:4
38×1/4+0.25×41又2分之一+20.5×1/4
=38/0.25+0.25*41.5+20.5*0.25
=(38+41.5+20.5)*0.25
=80*0.25
=20
NO5:
(1/12+1/15)×12×15
=(1/12×12×15)+(1/15×12×15)
=15+12
=27
NO6:
(7/13×5/11)×13×11
=(7/13×13×11)*(5/11×13×11)
=77*65
=70*65+7*65
=4550+455
=5005
NO7 :
42×9/24-3/8
=42*3/8-3/8
=41*3/8
=40*3/8+3/8
=15+3/8
NO:8
三十九又五分之二÷13
=(39 2/5)/13
=39/13+(2/5)/13
=3+2/65
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