早教吧作业答案频道 -->英语-->
假如你叫李华,打算参加由美国Kent中学推出的为期半年的交换生项目(StudentExchangeProgram).请给对方写信简要陈述参加该项目的理由,内容包括:1.交朋友,相互介绍本国文化;2.家
题目详情
假如你叫李华,打算参加由美国 Kent中学推出的为期半年的交换生项目(Student Exchange Program).请给对方写信简要陈述参加该项目的理由,内容包括:
1.交朋友,相互介绍本国文化;
2.家庭寄宿(homestay),体验生活,提高口语能力;
3.观光旅游,增长见识,了解风土人情.
注意:1.词数100左右; 2.可以适当增加细节,以使行文连贯.
1.交朋友,相互介绍本国文化;
2.家庭寄宿(homestay),体验生活,提高口语能力;
3.观光旅游,增长见识,了解风土人情.
注意:1.词数100左右; 2.可以适当增加细节,以使行文连贯.
▼优质解答
答案和解析
Dear Sir or Madam,
Hello!I am Li Hua,a senior 1 student.I have just learned about this six-month Student Exchange Program in Kent,which I take a great interest in and I am writing to apply for it.The reasons are as follows:
First and foremost,I can make an acquaintance of many new friends,and we can introduce our own culture to each other.Secondly,homestay enables me to have an authentic experience of the local life and meanwhile improve my spoken English.Thirdly,by sightseeing,I can make a close exploration of the local customs and practice,thus expanding my knowledge.
I will be glad if I get the precious opportunity and I am looking forward to your reply.
Hello!I am Li Hua,a senior 1 student.I have just learned about this six-month Student Exchange Program in Kent,which I take a great interest in and I am writing to apply for it.The reasons are as follows:
First and foremost,I can make an acquaintance of many new friends,and we can introduce our own culture to each other.Secondly,homestay enables me to have an authentic experience of the local life and meanwhile improve my spoken English.Thirdly,by sightseeing,I can make a close exploration of the local customs and practice,thus expanding my knowledge.
I will be glad if I get the precious opportunity and I am looking forward to your reply.
看了假如你叫李华,打算参加由美国K...的网友还看了以下:
高中数学题求助,快~已知数列{an}中,a1=1/2,点(n,2a(n+1)-an)在直线y=x上 2020-06-03 …
若复数z满足z^n=1,其中n属于N+,则1+z+z^2+...+z^n=答案是:1或n+1我却算 2020-06-12 …
观察下列各式,直接写出答案(x-1)(x+1)=x^2-1(x-1)(x^2+x+1)=x^3-1 2020-07-15 …
我们知道1+2+3+……+n=2分之1n(n+1),其中n是自然数.现在来研究一个类似的问题:1× 2020-07-21 …
观察下面个式:(x-1)(x+1)=x^2-1;(x-1)(x^2+x+1)=x^3-1;(x-1 2020-07-22 …
在数列{an}中,a1=1,an+1=1-1/(4an),bn=2/((2an)-1).求证数列{ 2020-07-28 …
用数学归纳法证明1∕n+1∕(n+1)+1∕(n+2)+…+1∕(n的平方)〉1,其中n〉1 2020-08-01 …
1)1111=-类似的,我们还可以得到:=()n(n+1)nn+1n(n+2)1=().(其中n是正 2020-11-03 …
已知一列非零向量an满足a1=(x1,y1)an=(xn,yn)=1/2(x(n-1)-y(n-1) 2020-12-07 …
在数列{an}中,a1=1,a(n+1)=1-1/4an,bn=2/(2an-1),其中n∈N*(1 2020-12-09 …