早教吧 育儿知识 作业答案 考试题库 百科 知识分享

这是数据结构的实验题,谁能帮我解一下,感激不尽哦设计一个有序顺序表(数据元素从小到有序),有序顺序表数据类型定义如下:?逻辑结构:有序线性表?存储结构:顺序?操作集

题目详情
这是数据结构的实验题,谁能帮我解一下,感激不尽哦
设计一个有序顺序表(数据元素从小到有序),有序顺序表数据类型定义如下:
?逻辑结构:有序线性表
?存储结构:顺序
?操作集合:初始化、插入、删除,具体说明如下:
(1)ListInitiate(L) 初始化线性表,生成一个空表
(2)ListInsert(L,x) 在有序表L中插入数据元素x,使得新表仍然有序
(3)ListDelete(L,x) 在有序表L中删除数据元素x
并通过主函数验证所设计的有序顺序表的正确性。

提示:插入操作时,从顺序表的第一个数据元素开始,逐个比较list[i]值和x的值,当list[i]值小于等于x时,进行下一个结点的比较;否则就找到了插入结点的合适位置,向后移动元素,腾出空位,插入元素x;当比较到最后一个结点仍有list[i]值小于等于x时,则把x插入到顺序表表尾。
▼优质解答
答案和解析
以前写的东西……
/*
作者:
学号:
题目:P50 2-3
时间:2010.3.24
说明:仅不带头结点的双循环链表类。提供一个迭代器类。
可以通过迭代器访问它指向的数据元素,迭代器可以向前/向后移动,可以被赋值,
可以判相等,可以删除迭代器指向的数据此元素。
思路:不带头结点需要特殊判断链表为空的情况,删除时要格外小心。
其他:注意迭代器不需要析构函数,它不申请额外空间
*/
#include
#include
using namespace std;
//线性表抽象类
template
class List{
public:
virtual ~List(){};

virtual void clear() = 0;
virtual int length() const = 0;
virtual void insert( int i, const T &x ) = 0;
virtual void remove( int i ) = 0;
virtual int search( const T& ) const = 0;
virtual T visit( int i ) const = 0;
virtual void traverse() const = 0;
};
class OutOfBound{
public:
OutOfBound(){
cout << "访问超出范围!" << endl;
system("pause");
}
};
class EraseError{
public:
EraseError(){
cout << "删除了不存在的结点,删除失败!" << endl;
system("pause");
};
};
class Exception{};
// 双链表类
template
class Linklist: public List
{
private:
struct Node
{
T data;
Node *next, *prev;

Node( const T &x, Node *p = NULL, Node *n = NULL) { data = x; prev = p; next = n; }
Node(): next(NULL), prev(NULL){}
~Node(){}
};

public:
//迭代器类
class Iterator
{
friend bool operator == ( Iterator a, Iterator b ) {
return ( a.it == b.it ) ? true : false;
}

private:
Node *it;

public:
T visit(){ if ( it == NULL ) throw OutOfBound(); return it->data; }

//赋值迭代器
Iterator & operator = ( Iterator x ){
it = x.it;
return *this;
}

//自增、自减迭代器
Iterator & operator ++(){
if ( it == NULL || it->next == NULL ) throw OutOfBound();
it = it->next;
return *this;
}
Iterator operator ++ (int) {
if ( it == NULL || it->next == NULL ) throw OutOfBound();
Iterator v;
v.it = it;
it = it->next;
return v;
}
Iterator & operator --() {
if( it == NULL || it->next == NULL ) throw OutOfBound();
it = it->prev;
return *this;
}
Iterator operator --(int) {
if ( it == NULL || it->next == NULL ) throw OutOfBound();
Iterator v;
v.it = it;
it = it->prev;
return v;
}

Iterator(){ it = NULL; }
~Iterator() {}
friend class Linklist;
};

private:
Node *head, *tail;
int l;

//移动迭代器到指定结点
Node* move( int i ) const {
Node *p = head;
if ( i < 0 || i > l ) throw OutOfBound();
while (i--) p = p->next;
return p;
}
public:
Linklist();
~Linklist(){ clear(); delete head; delete tail; }

void clear();
int length() const { return l; }
int search( const T &x ) const;
void insert( int i, const T &x );
void remove( int i );
void traverse() const;
T visit( int i ) const;
void erase( Iterator v ){
//删除迭代器指定的结点
try{
v.it->prev->next = v.it->next;
v.it->next->prev = v.it->prev;
if ( v.it == head && l != 0 ) head = head->next;
delete v.it;
--l;
if ( l == 0 ){ head = NULL; tail = NULL; }
} catch ( Exception() ) { throw( EraseError()); };
}
//FUCK
Iterator begin() const { Iterator v; v.it = head; return v; }
Iterator end() const { Iterator v; v.it = tail; return v; }
};
template
Linklist::Linklist() {
head = NULL; tail = NULL; l = 0;
}
//清空链表
template
void Linklist::clear() {
Node *p = head, *q;
for ( int i = 0; i < l; ++i ) {
q = p->next;
delete p;
p = q;
}
head = NULL; tail = NULL;
l = 0;
}
//插入链表
template
void Linklist::insert( int i, const T &x ) {
Node *pos, *tmp;

if ( l == 0 ) {
head = new Node( x, NULL, NULL);
head->prev = head;
head->next = head;
tail = head;
} else {
pos = move(i-1);
tmp = new Node( x, pos, pos->next );
pos->next->prev = tmp;
pos->next = tmp;
if ( i == l ) tail = tmp;
}

++l;
}
//移除链表指定结点
template
void Linklist::remove( int i )
{
try{
Node *pos;
pos = move(i);
pos->prev->next = pos->next;
pos->next->prev = pos->prev;
if ( i == 0 && l != 0 ) head = head->next;
delete pos;
--l;
if ( l == 0 ){ head = NULL; tail = NULL; }
} catch ( Exception() ) { throw( EraseError()); };
}
//搜寻指定结点
template
int Linklist::search( const T &x ) const
{
Node *p = head;
int i = 0;

while ( i != l && p->data != x ) { p = p->next; ++i; }
if ( p->data == x ) return i; else return -1;
}
//访问结点
template
T Linklist::visit( int i ) const
{
Node *p = move(i);
return p->data;
}
//遍历
template
void Linklist::traverse() const
{
Node *p = head;
for ( int i = 0; i < l; ++i ){
cout << p->data << " ";
p = p->next;
}
cout << endl;
}
int main(){
int i, n, x;
Linklist a;
Linklist::Iterator v1, v2;

//cin >> n;
cout << "这是一个自动范例,插入 1 2 3 4 5 " << endl;
n = 5;
for ( int i = 0; i != n; ++i ){
x = i + 1;
//cin >> x;
a.insert(i, x);
}
a.traverse();
cout << a.visit(3) << endl;
cout << a.length() << endl;
a.remove(3);
cout << a.search(x) << endl;
cout << a.search(0) << endl;
cout << a.visit(3) << endl;
a.traverse();

v1 = a.begin(); v2 = a.begin();
cout << "v1 == v2 " << (v1 == v2) << endl;
v1 = a.begin(); v2 = a.end();
cout << "v1 == v2 " << (v1 == v2) << endl;

for ( v1 = a.begin(); !(v1 == a.end()); ++v1 ){
cout << v1.visit() << endl;
a.erase(v1);
a.traverse();
}

system("pause");
return 0;
}
看了这是数据结构的实验题,谁能帮我...的网友还看了以下: