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1+sin2x+con2x=1+跟号sin（2x+π/4）这一步化简我看不懂谁能帮我梳理一下是1+sin2x+con2x=1+跟号2sin（2x+π/4）···sorrry···
题目详情
1+sin2x+con2x=1+跟号sin（2x+π/4）这一步化简我看不懂 谁能帮我梳理一下
是1+sin2x+con2x=1+跟号2sin（2x+π/4）···sorrry···
是1+sin2x+con2x=1+跟号2sin（2x+π/4）···sorrry···
▼优质解答
答案和解析
应该是 1+sin2x+cos2x=1+√2sin(2x+π/4)
1+sin2x+cos2x
=1+√2(√2/2·sin2x+√2/2·cos2x)
=1+√2(cosπ/4·sin2x+sinπ/4·cos2x)
=1+√2sin(2x+π/4)
1+sin2x+cos2x
=1+√2(√2/2·sin2x+√2/2·cos2x)
=1+√2(cosπ/4·sin2x+sinπ/4·cos2x)
=1+√2sin(2x+π/4)
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