已知函数f(x)=sin(x/3)cos(x/3)+√3cos^2(x/3)如果△ABC的三边a,b,c满足b^2=ac,且边b所对的角为x,试求x的范围及此时函数的值域.今天为止,过期作废

Question

已知函数f(x)=sin(x/3)cos(x/3)+√3cos^2(x/3)
如果△ABC的三边a,b,c满足b^2=ac,且边b所对的角为x,试求x的范围及此时函数的值域.今天为止,过期作废

Answer 1

∵b^2=ac
由余弦定理b^2=a^2+c^2-2accosx
cosx=(a^2+c^2-ac)/(2ac)=(a^2+c^2)/(2ac)-1/2≥(2ac)/(2ac)-1/2=1/2
∴0≤x≤π/3 (1)
f(x)=sin(x/3)cos(x/3)+√3cos^2(x/3)
=sin(2x/3+π/3)+√3/2
f(x)max=1+√3/2
由(1)知 π/3≤2x/3+π/3≤5π/9
∴f(x)min=sin(π//3)+√3/2=√3
∴函数的值域为[√3,1+√3/2]