已知Sn是等差数列{an}的前n项和,bn=Sn/n,①证:数列{bn}是等差数列②若S7=已知Sn是等差数列{an}的前n项和,bn=Sn/n,①证:数列{bn}是等差数列②若S7=7,S15=75,则数列{bn}的前n项和Tn为.

Question

已知Sn是等差数列{an}的前n项和,bn=Sn/n,①证:数列{bn}是等差数列 ②若S7=
已知Sn是等差数列{an}的前n项和,bn=Sn/n,①证:数列{bn}是等差数列 ②若S7=7,S15=75,则数列{bn}的前n项和Tn为.

Answer 1

设an-an-1=r
bn=Sn/n=n(an+a1)/2n=(an+a1)/2 b1=a1
bn-1=Sn-1/(n-1)=(n-1)an-1+a1)/2(n-1)=(an-1+a1)/2
bn-bn-1=(an+a1)/2-(an-1+a1)/2=(an-an-1)/2=r/2
所以数列{bn}是等差数列
S7=7*(a1+a1+6r)/2=7 a1+3r=1
S15=15*(a1+a1+14r)/2=75 a1+7r=5
所以a1=-2 r=1 b1=-2
Tn=n(b1+b1+(n-1)/2)/2=n(n-5)/4