早教吧作业答案频道 -->数学-->
正方体ABCD-A1B1C1D1中,O是上底面ABCD中心,若棱长为a,则三棱锥O-AB1D1的体积为.
题目详情
111111
▼优质解答
答案和解析
如图,在正方体ABCD-A11B11C11D11中,
O是上底面ABCD的中心,棱长为a,
∴对角线AC⊥平面BDD11B11,
∴三棱锥O-AB11D11的体积为
V三棱锥O-AB1D1=
•S△OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. V三棱锥O-AB1D1=
•S△OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. 三棱锥O-AB1D1=
•S△OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. 1D1=
•S△OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. 1=
•S△OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3.
1 1 13 3 3•S△OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. S△OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. △OB1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. 1D1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3. 1•AO
=
•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3.
1 1 13 3 3•
B1D1•OO1•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3.
1 1 12 2 2B11D11•OO11•AO
=
•
•
a•a•
a
=
a3.
故答案为:
a3.
1 1 13 3 3•
•
a•a•
a
=
a3.
故答案为:
a3.
1 1 12 2 2•
a•a•
a
=
a3.
故答案为:
a3.
2 2 2a•a•
a
=
a3.
故答案为:
a3.
2 2 22 2 2a
=
a3.
故答案为:
a3.
1 1 16 6 6a3.
故答案为:
a3. 3.
故答案为:
a3.
1 1 16 6 6a3. 3.
O是上底面ABCD的中心,棱长为a,
∴对角线AC⊥平面BDD11B11,
∴三棱锥O-AB11D11的体积为
V三棱锥O-AB1D1=
1 |
3 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
3 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
3 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
3 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
3 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
3 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
=
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
3 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
2 |
=
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
3 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
2 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
2 |
| ||
2 |
=
1 |
6 |
故答案为:
1 |
6 |
| ||
2 |
2 |
2 |
2 |
=
1 |
6 |
故答案为:
1 |
6 |
1 |
6 |
故答案为:
1 |
6 |
故答案为:
1 |
6 |
1 |
6 |
看了 正方体ABCD-A1B1C1...的网友还看了以下:
已知:如图,在直角坐标系中,直角三角形OAB,O为坐标原点,AB=1,OB=3,将△OAB绕着A点 2020-05-13 …
已知,如图,以△ABC的边AB为直径的○O交边AC于点D,且过点D的切线DE平分边BC,(1)求证 2020-05-16 …
选出与所给单词划线部分读音相同的一项1、h(o)meA.c(o)meB.g(o)C.d(o)cto 2020-05-17 …
··一道简单的数学题,先到的.对的.角D=90度,BD=CD,BO是角DBC的角平分线,CE垂直B 2020-06-03 …
如图,已知以Rt△ABC的边AB为直径作△ABC的外接圆⊙O,∠B的平分线BE交AC于D,交⊙O于 2020-06-27 …
A.袅袅(niǎo)照浦(bǔ)褒贬(bāo)B.灼灼(zhuó)亭皋(gāo)寒砧(zhàn)C 2020-06-29 …
选择:诺a>b>o,c<d<o,则一定有()A,c分之a>d分之bB,c分之a<d分之b选择:诺a 2020-06-29 …
进制换算(213)D=()B=()H=()O(69.625)D=()D=()B=()O(127)D 2020-07-19 …
已知点O(0,0)和点B(m,0)(m>0),动点P到O,B的距离比为2∶1,求P点轨迹和P点在什 2020-07-22 …
设A,B,C,D是一条直线上的四个点,O是直线外的一点,设O→A=3a,O→B=3b,C,D是线段 2020-07-24 …