下列分式方程有解的是（）A．2x+1+3x−1=6x2−1B．x2+1x＝0C．22x−1＝0D．1x−1＝1

Question

下列分式方程有解的是（　　）

A．(2)/(x+1)+(3)/(x−1)=(6)/(x2−1)
B．(x2+1)/(x)＝0
C．(2)/(2x−1)＝0
D．(1)/(x−1)＝1

(2)/(x+1)+(3)/(x−1)=(6)/(x2−1)
B．(x2+1)/(x)＝0
C．(2)/(2x−1)＝0
D．(1)/(x−1)＝1(2)/(x+1)22x+1x+1(3)/(x−1)=(6)/(x2−1)
B．(x2+1)/(x)＝0
C．(2)/(2x−1)＝0
D．(1)/(x−1)＝1(3)/(x−1)33x−1x−1(6)/(x2−1)
B．(x2+1)/(x)＝0
C．(2)/(2x−1)＝0
D．(1)/(x−1)＝1(6)/(x2−1)66x2−1x2−1x2−1x2−12−1
(x2+1)/(x)＝0
C．(2)/(2x−1)＝0
D．(1)/(x−1)＝1(x2+1)/(x)x2+1x2+1x2+1x2+12+1xx
(2)/(2x−1)＝0
D．(1)/(x−1)＝1(2)/(2x−1)222x−12x−1
(1)/(x−1)＝1(1)/(x−1)11x−1x−1

Answer 1

A、把分式方程化为整式方程后算出来的结果为x=1，最简公分母为0，故无解．
B、把分式方程化为整式方程后得到x²2+1=0，x²2=-1这是不可能的，故无解．
C、(2)/(2x−1)＝0，那么分子应为0．可分子为2，故无解．
D、化为整式方程后算出来的结果为x=2，最简公分母不为0，故有解．
故选D． (2)/(2x−1)2222x−12x−12x−1＝0，那么分子应为0．可分子为2，故无解．
D、化为整式方程后算出来的结果为x=2，最简公分母不为0，故有解．
故选D．