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求证:(a+1/a)^2+(b+1/b)^2+(ab+1/ab)^2=4+(a+1/a)(b+1/b)(ab+1/ab)
题目详情
求证:(a+1/a)^2+(b+1/b)^2+(ab+1/ab)^2=4+(a+1/a)(b+1/b)(ab+1/ab)
▼优质解答
答案和解析
左边=a^2+1/a^2+2+b^2+1/b^2+2+a^2b^2+1/(a^2*b^2)+2
= a^2+1/a^2+b^2+1/b^2+a^2b^2+1/(a^2*b^2)+6
右边=4+2+ a^2+1/a^2+b^2+1/b^2+a^2b^2+1/(a^2*b^2)
=a^2+1/a^2+b^2+1/b^2+a^2b^2+1/(a^2*b^2)+6
左边=右边.
= a^2+1/a^2+b^2+1/b^2+a^2b^2+1/(a^2*b^2)+6
右边=4+2+ a^2+1/a^2+b^2+1/b^2+a^2b^2+1/(a^2*b^2)
=a^2+1/a^2+b^2+1/b^2+a^2b^2+1/(a^2*b^2)+6
左边=右边.
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