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(Inx/x+1)+(1/x)-(Inx/x-1)=(1/1-x^2)[2Inx-(x^2-1/x)]由前推到后的步骤,
题目详情
(Inx/x+1)+(1/x)-(Inx/x-1)=(1/1-x^2)[2Inx-(x^2-1/x)] 由前推到后的步骤,
▼优质解答
答案和解析
Inx /(x+1)+(1/x) - Inx /(x-1) @
= lnx [ 1/(x+1) + 1/(1-x) ] -1/x
= lnx * 2 /(1-x^2) - 1/x
[1/(1-x^2)] [2Inx-(x^2-1) / x ] @@
= lnx * 2 /(1-x^2) +1/x
=> @ = @@
= lnx [ 1/(x+1) + 1/(1-x) ] -1/x
= lnx * 2 /(1-x^2) - 1/x
[1/(1-x^2)] [2Inx-(x^2-1) / x ] @@
= lnx * 2 /(1-x^2) +1/x
=> @ = @@
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