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计算:(1)−12+12÷[(−112)3+(−12)2]×|−2.52|−12;(2)(−1)5×{[423÷(−4)+(−114)×(−0.4)]÷(−13)−2};(3)[(1−13)2−(−123)÷(−118)]×(−112)3+512×(−511);(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(

题目详情

1
2
+
1
2
÷[(−1
1
2
)3+(−
1
2
)2]×|−2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
1
2
1122
1
2
1122(−1
1
2
)3+(−
1
2
)2]×|−2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
(−1
1
2
)3+(−
1
2
)2]×|−2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
1
2
11223+(−
1
2
)2]×|−2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
(−
1
2
)2]×|−2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
(−
1
2
)2]×|−2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
1
2
11222]×|−2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
2.52|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
2|−
1
2

(2)(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
1
2
1122
(−1)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
)5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
5×{[4
2
3
÷(−4)+(−1
1
4
)×(−0.4)]÷(−
1
3
)−2};
(3)[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
2
3
2233
1
4
1144
1
3
1133
[(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
(1−
1
3
)2−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
1
3
11332−(−1
2
3
)÷(−1
1
8
)]×(−1
1
2
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
2
3
2233
1
8
1188
1
2
1122)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
)3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
3+5
1
2
×(−
5
11
);
(4){[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
1
2
1122
5
11
551111
{[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
{[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
{[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
[(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
(1−0.9)2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
2×10−0.09]2×100−0.009}2×[(−2)3+2
2
3
×3].
2×100−0.009}2×[(−2)3+2
2
3
×3].
2×[(−2)3+2
2
3
×3].
(−2)3+2
2
3
×3].
(−2)3+2
2
3
×3].
3+2
2
3
×3].
2
3
2233
▼优质解答
答案和解析
(1)原式=-
1
2
+
1
2
÷[-
27
8
+
1
4
]×6.25-
1
2

=-1+
1
2
×(-
8
25
)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
2
111222+
1
2
÷[-
27
8
+
1
4
]×6.25-
1
2

=-1+
1
2
×(-
8
25
)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
2
111222÷[-
27
8
+
1
4
]×6.25-
1
2

=-1+
1
2
×(-
8
25
)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
27
8
272727888+
1
4
]×6.25-
1
2

=-1+
1
2
×(-
8
25
)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
4
111444]×6.25-
1
2

=-1+
1
2
×(-
8
25
)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
2
111222
=-1+
1
2
×(-
8
25
)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
2
111222×(-
8
25
)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
8
25
888252525)×
25
4

=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
25
4
252525444
=-1-1
=-2;
(2)原式=-1×{[
14
3
×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
14
3
141414333×(-
1
4
)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
4
111444)+
5
4
×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
5
4
555444×
2
5
]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
2
5
222555]÷(-
1
3
)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
3
111333)-2}
=-1×{[-
7
6
+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
7
6
777666+
1
2
]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
2
111222]÷(-
1
3
)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
1
3
111333)-2}
=-1×{-
2
3
×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
2
3
222333×(-3)-2}
=-1×0
=0;
(3)原式=[
4
9
-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
4
9
444999-
5
3
×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
5
3
555333×
8
9
]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
8
9
888999]×(-
27
8
)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
27
8
272727888)+
11
2
×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
11
2
111111222×(-
5
11

=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
5
11
555111111)
=-
28
27
×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
28
27
282828272727×(-
27
8
)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
27
8
272727888)-
5
2

=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
5
2
555222
=
7
2
-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
7
2
777222-
5
2

=1;
(4)原式={[0.01×10-0.09]2×100-0.009}2×(-8+8)
={[0.01×10-0.09]2×100-0.009}2×0
=0.
5
2
555222
=1;
(4)原式={[0.01×10-0.09]22×100-0.009}22×(-8+8)
={[0.01×10-0.09]22×100-0.009}22×0
=0.