已知x=-8,y=1/8,n为正整数,求x^2n+1*y^2n+1的值

Question

已知x=-8,y=1/8,n为正整数,求x^2n+1*y^2n+1的值

Answer 1

x^2n+1*y^2n+1
=(-8)^(2n+1)(1/8)^(2n+1)
=(-8×(1/8))^(2n+1)
=(-1)^(2n+1)
=-1