解分式方程x+1/(4x-6)=(a²+3a+1)/2a 急~

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答案和解析

x+1/(4x-6)=(a²+3a+1)/2a
2ax(4x-6)+2a=(a²+3a+1)(4x+6)
4ax²-(2a²+12a+2)x+(3a²+10a+3)=0
[2ax-(3a+1)]*[2x-(a+3)]=0
x1=(3a+1)/(2a)
x2=(a+3)/2

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