如何用matlab解二元微分方程Dx=20x*(1-x/2500)-0.0001*x^2-0.03y*x^2Dy=30y*(1-y/1000)-0.0003*y^2-0.015

Question

如何用matlab解二元微分方程
Dx=20x*(1-x/2500)-0.0001*x^2-0.03y*x^2
Dy=30y*(1-y/1000)-0.0003*y^2-0.015

Answer 1

>> z=dsolve('Dx=20*x*(1-x/2500)-0.0001*x^2-0.03*y*x^2,Dy=30*y*(1-y/1000)-0.0003*y^2-0.015','t');
z.x
z.y
ans =
exp(20*t)/(Int(3/1010000*exp(20*t)*(5002727+500*99999798^(1/2)*tanh(3/2000*99999798^(1/2)*t+3/2000*99999798^(1/2)*C2)),t)+C1)
ans =
50000/101+5/101*99999798^(1/2)*tanh(3/2000*99999798^(1/2)*t+3/2000*99999798^(1/2)*C2)
>>