当a=负的1/2+根号5时,化简9-6a+a^2/a-3加(根号下a^2-2a+1)/a^2-a

Question

当a=负的1/2+根号5时,化简9-6a+a^2/a-3加(根号下a^2-2a+1)/a^2-a

Answer 1

a=-(1/(2+√5)=2-√5
(9-6a+a²)/(a-3)+√(a²-2a+1)/(a²-a)
=(a-3)²/(a-3)+√(a-1)²/a(a-1)
=a-3+(a-1)/a(a-1)
=a+3+1/a
=2-√5+3+1/(2-√5)
=5-√5-(2+√5)
=5-√5-2-√5
=3-2√5