随机变量相关问题答案给的是1-2e^(-1)

Question

Answer 1

f(x,y)=∫[0,1]dx∫[0,1-x]e^(2x+y)dy

f(x,y)=∫[0,1]dx∫[0,1-x]e^(2x+y)dy

=∫[0,1]e^2xdx∫[0,1-x]e^ydy

=∫[0,1]e^2xdx∫[0,1-x]e^ydy

=∫[0,1]e^2x*{e^(1-x)-1}dx

=∫[0,1]e^2x*{e^(1-x)-1}dx

=∫[0,1]{e^(1+x)-e^(2x)}dx

=∫[0,1]{e^(1+x)-e^(2x)}dx

答案对不上,你的题目看不清.

答案对不上,你的题目看不清.