(x^2-4/x^3+x+1)^2÷[x^3-3x^2+2x/(x-1)(x^2+x+1)]^2·(x/x+2)^3怎么分解因式.快没时间了,

Answer 1

原式=[(x+2)²(x-2)²/(x²+x+1)²]*[(x-1)²(x²+x+1)²/x²(x-1)²(x-2)²]*[x³/(x+2)³]
=x³(x+2)²(x-2)²(x-1)²(x²+x+1)²/[x²(x²+x+1)²(x-1)²(x-2)²(x+2)³]
=x/(x+2)