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分式的运算因为1/1*3=1/2*(1-1/3),1/3*5=1/2*(1/3-1/5),,1/17*19=,所以1/1*3+1/3*5+1/5*7+~+1/17*19=1/2(1-1/3+1/3-1/5+1/5-1/7=~+1/17-1/19)=1/2(1-1/19)=9/19根拒式子化简:1/(X-1)(X-2)+1/(X-2)(X-3)+1/(X-3)(X-4)=?
题目详情
分式的运算
因为1/1*3=1/2*(1-1/3),1/3*5=1/2*(1/3-1/5),,1/17*19=,所以1/1*3+1/3*5+1/5*7+~+1/17*19=1/2(1-1/3+1/3-1/5+1/5-1/7=~+1/17-1/19)=1/2(1-1/19)=9/19
根拒式子化简:1/(X-1)(X-2)+1/(X-2)(X-3)+1/(X-3)(X-4)=?
因为1/1*3=1/2*(1-1/3),1/3*5=1/2*(1/3-1/5),,1/17*19=,所以1/1*3+1/3*5+1/5*7+~+1/17*19=1/2(1-1/3+1/3-1/5+1/5-1/7=~+1/17-1/19)=1/2(1-1/19)=9/19
根拒式子化简:1/(X-1)(X-2)+1/(X-2)(X-3)+1/(X-3)(X-4)=?
▼优质解答
答案和解析
1/(X-1)(X-2)=1/(X-2)-1/(X-1)1/(X-2)(X-3)=1/(X-3)-1/(X-2)1/(X-3)(X-4)=1/(X-4)-1/(X-3)1/(X-1)(X-2)+1/(X-2)(X-3)+1/(X-3)(X-4)=1/(X-2)-1/(X-1)+1/(X-3)-1/(X-2)+1/(X-4)-1/(X-3)=1/(X-4)-1/(X-1)=3/(X-1)(X-4)
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