R是圆x^2+y^2=1和椭圆（x-1)^2/9+y^2/8=1之间的区域把椭圆的公式变成极坐标系统,其极坐标系统公式应该为a+rcos(theta)=br,然后找出a和b的值.英文原题为LetRbetheregionbetweenthecirclex^2+y

Question

R是圆x^2 +y^2 = 1 和椭圆 （x-1)^2/9 + y^2/8 =1 之间的区域
把椭圆的公式变成极坐标系统 ,其极坐标系统公式应该为 a + r cos(theta) = br ,然后找出a和b的值.
英文原题为
Let R be the region between the circle x^2 +y^2 = 1 and the ellipse （x-1)^2/9 + y^2/8 =1
Show that the equation of the given ellipse in polar coordinates has the form a + r cos(theta) = br and find the values of a and b.

Answer 1

R是圆x^2+y^2=1和椭圆[(x-1)^2]/9+(y^2)/8=1围成的区域.(a)画出R的草图.这问你自己画.(b)证明椭圆[(x-1)^2]/9+(y^2)/8=1的极坐标方程形式为a+rcosθ=br,并求出a,b的值.8(x-1)^2+9y^2=729x^2+9y^2=64+16x+x^2=(8+x)^2...