已知A.B.X.Y是有理数.且(X-A)的绝对值+(Y+B)^2=0求(A^2+AY-BX+B^2)/(X+Y)除以(A^2+AX+BY-B^2)/(A+B)的值

Question

已知A.B.X.Y是有理数.且(X-A)的绝对值+(Y+B)^2=0
求(A^2+AY-BX+B^2)/(X+Y)除以(A^2+AX+BY-B^2)/(A+B)的值

Answer 1

|x-a|+(y-b)²=2那么有x-a=0即x=a,y+b=0即y=-b[(a²+ay-bx+b²)/(x+y)]/[(a²+ax+by-b²)/(a+b)]=[(a²-ab-ab+b²)/(a-b)]/[(a²+a²-b²-b²)/(a+b)]=[(a²-2ab+b...