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求答案(1+1/2002+1/2003+1/2004)*(1/2002+1/2003+1/2004+1/2005)-(1+1/2002+1/2003+1/2004+1/2005)*(1/20(1+1/2002+1/2003+1/2004)*(1/2002+1/2003+1/2004+1/2005)-(1+1/2002+1/2003+1/2004+1/2005)*(1/2002+1/2003+1/2004)=

题目详情
求答案(1+1/2002+1/2003+1/2004)*(1/2002+1/2003+1/2004+1/2005)-(1+1/2002+1/2003+1/2004+1/2005)*(1/20
(1+1/2002+1/2003+1/2004)*(1/2002+1/2003+1/2004+1/2005)-(1+1/2002+1/2003+1/2004+1/2005)*(1/2002+1/2003+1/2004)=
▼优质解答
答案和解析
令a=1/2002+1/2003+1/2004
则原式=(1+a)(a+1/2005)-(1+a+1/2005)a
=(1+a)a+1/2005(1+a)-(1+a)a-1/2005a
=1/2005(1+a)-1/2005a
=1/2005+1/2005a-1/2005a
=1/2005
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