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3/（x-2）-4/(x-1)=1/(x-4)-2/(x-3) 大概是要用换元法的...
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3/（x-2）-4/(x-1)=1/(x-4)-2/(x-3) 大概是要用换元法的...
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答案和解析
3/(x-2)+2/(x-3)=4/(x-1)+1/(x-4)
(5x-6)/(x^2-5x+6)=(5x-17)/(x^2-5x+4)
(5x-6)(x^2-5x+4)=(5x-17)(x^2-5x+6)
5x^3-31x^2-10x-24=5x^3-42x^2-75x-102
11x^2+65x+78=0
x=(-65±√793)/22
(5x-6)/(x^2-5x+6)=(5x-17)/(x^2-5x+4)
(5x-6)(x^2-5x+4)=(5x-17)(x^2-5x+6)
5x^3-31x^2-10x-24=5x^3-42x^2-75x-102
11x^2+65x+78=0
x=(-65±√793)/22
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