早教吧作业答案频道 -->数学-->
LINGO线性规划 怎么编写?min=10*(x1-155)+10*(x2-258)+30*(98-x3)+30*(106-x4)+30*(123-x5)+30*(x6-135)+30*(138-x7)+30*(140-x8)+30*(x9-150)+30*(x10-180)约束x051x052x053x054x055x056x057x0589 101x05-x053x0515x0515x0515x0515x0515x051
题目详情
LINGO线性规划 怎么编写?
min=10*(x1-155)+10*(x2-258)+30*(98-x3)+30*(106-x4)+30*(123-x5)+30*(x6-135)+30*(138-x7)+30*(140-x8)+30*(x9-150)+30*(x10-180)
约束
\x051\x052\x053\x054\x055\x056\x057\x058
9 10
1\x05-\x053\x0515\x0515\x0515\x0515\x0515\x0515\x0515\x0515
2\x053\x05-\x0515\x0515\x0515\x0515\x0515\x0515\x0515\x0515
3\x0515\x0515\x05-\x058\x058\x058\x058\x058\x058\x058
4\x0515\x0515\x058\x05-\x058\x058\x058\x058\x058\x058
5\x0515\x0515\x058\x058\x05-\x058\x058\x058\x058\x058
6\x0515\x0515\x058\x058\x058\x05-\x058\x058\x058\x058
7\x0515\x0515\x058\x058\x058\x058\x05-\x058\x058\x058
8\x0515\x0515\x058\x058\x058\x058\x058\x05-\x058\x058
9\x0515\x0515\x058\x058\x058\x058\x058\x058\x05-\x058
10\x0515\x0515\x058\x058\x058\x058\x058\x058\x058\x05-
|xi-xj|>=xij(i不等于j)
x1=155;
x2=258;
x3=89;
x4=96;
x5=110;
x6=135;
x7=124;
x8=126;
x9=150;
x10=180;
min=10*(x1-155)+10*(x2-258)+30*(98-x3)+30*(106-x4)+30*(123-x5)+30*(x6-135)+30*(138-x7)+30*(140-x8)+30*(x9-150)+30*(x10-180)
约束
\x051\x052\x053\x054\x055\x056\x057\x058
9 10
1\x05-\x053\x0515\x0515\x0515\x0515\x0515\x0515\x0515\x0515
2\x053\x05-\x0515\x0515\x0515\x0515\x0515\x0515\x0515\x0515
3\x0515\x0515\x05-\x058\x058\x058\x058\x058\x058\x058
4\x0515\x0515\x058\x05-\x058\x058\x058\x058\x058\x058
5\x0515\x0515\x058\x058\x05-\x058\x058\x058\x058\x058
6\x0515\x0515\x058\x058\x058\x05-\x058\x058\x058\x058
7\x0515\x0515\x058\x058\x058\x058\x05-\x058\x058\x058
8\x0515\x0515\x058\x058\x058\x058\x058\x05-\x058\x058
9\x0515\x0515\x058\x058\x058\x058\x058\x058\x05-\x058
10\x0515\x0515\x058\x058\x058\x058\x058\x058\x058\x05-
|xi-xj|>=xij(i不等于j)
x1=155;
x2=258;
x3=89;
x4=96;
x5=110;
x6=135;
x7=124;
x8=126;
x9=150;
x10=180;
▼优质解答
答案和解析
model:
sets:
point/1..10/:x;
road(point,point)|&1#gt#&2:a;
endsets
data:
a=
3
1515
15158
151588
1515888
15158888
151588888
1515888888
15158888888;
enddata
min=10*(x(1)-155)+10*(x(2)-258)+30*(98-x(3))+30*(106-x(4))+30*(123-x(5))+30*(x(6)-135)+30*(138-x(7))+30*(140-x(8))+30*(x(9)-150)+30*(x(10)-180);
@for(road(i,j):@abs(x(i)-x(j))>=a(i,j));
x(1)<=599;
x(1)>=155;
x(2)<=744;
x(2)>=258;
x(3)<=98;
x(3)>=89;
x(4)<=106;
x(4)>=96;
x(5)<=124;
x(5)>=110;
x(6)<=576;
x(6)>=135;
x(7)<=138;
x(7)>=124;
x(8)<=140;
x(8)>=126;
x(9)<=591;
x(9)>=150;
x(10)<=657;
x(10)>=180;
end
sets:
point/1..10/:x;
road(point,point)|&1#gt#&2:a;
endsets
data:
a=
3
1515
15158
151588
1515888
15158888
151588888
1515888888
15158888888;
enddata
min=10*(x(1)-155)+10*(x(2)-258)+30*(98-x(3))+30*(106-x(4))+30*(123-x(5))+30*(x(6)-135)+30*(138-x(7))+30*(140-x(8))+30*(x(9)-150)+30*(x(10)-180);
@for(road(i,j):@abs(x(i)-x(j))>=a(i,j));
x(1)<=599;
x(1)>=155;
x(2)<=744;
x(2)>=258;
x(3)<=98;
x(3)>=89;
x(4)<=106;
x(4)>=96;
x(5)<=124;
x(5)>=110;
x(6)<=576;
x(6)>=135;
x(7)<=138;
x(7)>=124;
x(8)<=140;
x(8)>=126;
x(9)<=591;
x(9)>=150;
x(10)<=657;
x(10)>=180;
end
看了 LINGO线性规划 怎么编写...的网友还看了以下:
用竖式计算,带﹡的要验算:﹡524÷6=39×40=8.9+5.8=﹡46×25=650÷5=6. 2020-04-07 …
5道应用题,1.某公司10家企业去年上缴税款(单位;万元)数额如下:8.6,7.8,9.5,8.8 2020-05-13 …
Matlab 将离散点拟合画出图形之后求出相应横坐标Y=[0.8,2.1,3.3,3.6,3,3, 2020-05-16 …
口算.1-710=6.3+7=0.25×4=5.1÷0.01=11.5+9.5=8+5.2=12. 2020-07-09 …
5/8*4/9*5/8*1/9+5/8*4/9用简便方法计算速回答.谢谢,详细过程. 2020-07-17 …
计算下面各题(1)24×23÷3÷8(2)35×58÷14-12(3)152×5.7+5.9×7. 2020-07-18 …
1+5+8+155+866+827+55455+55555+85566+855485+459545 2020-07-18 …
9/5+8/3除以9/413/11X7/5+7/2X13/2计算 2020-10-31 …
请具体讲解一下分数的加,减,乘,除法的运算方法还有分数怎么比较大小,1(1/2)的倒数是2/3是怎么 2020-11-28 …
A、B,C,D四种蛋白质的混合液,其pI值分别为4.9,5.8,6.5,7.8...看补充!A、B、 2020-12-23 …