((log(2)5)^2-4log(2)5+4)^(1/2)+log(2)1/5=?

Question

((log(2)5)^2-4log(2)5+4)^(1/2)+log(2)1/5=?

Answer 1

为了方便书写,我们将t代指log(2)5,且有log(2)1/5=-log(2)5=-t于是将上面的化为：（t²-4t+4）^(1/2)-t=（t-2）²^(1/2)-tt=log(2)5＞log(2)4=2于是t＞2（t-2）²^(1/2)-t=t-2-t=-2所以原式=-2...