早教吧作业答案频道 -->英语-->
英语翻译根据提示写一张延期举行报告会的通知.①推迟原因:王华教授因突然生病不能来校,据医生估计她几天内可以康复.②另定时间为4月20日星期四上午九点.③地址是新教学楼大厅.④报
题目详情
英语翻译
根据提示写一张延期举行报告会的通知.
①推迟原因:王华教授因突然生病不能来校,据医生估计她几天内可以康复.
②另定时间为4月20日星期四上午九点.
③地址是新教学楼大厅.
④报告内容是计算机科学.
⑤出席者:信息系(可能是计算机系吧,意思差不多就可以)师生必须参加,欢迎其他系师生参加.
文章没规定单词数,只要把上面的要求连贯起来,写成个小短文就可以了,
根据提示写一张延期举行报告会的通知.
①推迟原因:王华教授因突然生病不能来校,据医生估计她几天内可以康复.
②另定时间为4月20日星期四上午九点.
③地址是新教学楼大厅.
④报告内容是计算机科学.
⑤出席者:信息系(可能是计算机系吧,意思差不多就可以)师生必须参加,欢迎其他系师生参加.
文章没规定单词数,只要把上面的要求连贯起来,写成个小短文就可以了,
▼优质解答
答案和解析
An Announcement
Fellow students,
May we have your attention please?We have something important to tell you.Because Professor Wang who will give us the speech fell ill and the docter said he won't recover till several days after,the speech will be put off until 9:00am,Thurday,April 20th,and is to be held in the hall of the new Teaching Building.The speech is about the computer science,all students of Information Department are required to attend it.And we also hope students from other departments can join us.
That's all,thank you.
Students' Union
Fellow students,
May we have your attention please?We have something important to tell you.Because Professor Wang who will give us the speech fell ill and the docter said he won't recover till several days after,the speech will be put off until 9:00am,Thurday,April 20th,and is to be held in the hall of the new Teaching Building.The speech is about the computer science,all students of Information Department are required to attend it.And we also hope students from other departments can join us.
That's all,thank you.
Students' Union
看了英语翻译根据提示写一张延期举行...的网友还看了以下:
如图表示果蝇某正常基因片段控制合成多肽的过a-d表示4种基因突变.a丢失T/A.b由T/A变为C/ 2020-05-17 …
下图表示果蝇某正常基因片段控制合成多肽的过程。a—d表示4种基因突变。a丢失T/A,b由T/A变为 2020-05-17 …
(2010•徐汇区二模)如图表示果蝇某正常基因片段控制合成多肽的过程.a-d表示4种基因突变.a丢 2020-05-17 …
果蝇每一代出现的基因突变有()个求过程果蝇约有10^4对基因,假定每个基因的突变率.都是10^-5 2020-05-23 …
1.证明:因为直线和抛物线交于A,B两点,所以可得方程组{4x-y-1=0可得A,B两{x^2=2 2020-06-03 …
普通野生稻含有3.75×10∧4对基因,假定每个基因的突变率都是10∧-5,那么在约有10∧7个个 2020-06-28 …
果蝇共有3对常染色体,编号为Ⅱ、Ⅲ、Ⅳ,还有一对性染色体XY.果蝇γ(如图所示)的4种突变性状分别由 2020-11-02 …
(2009•潍坊一模)如图表示果蝇某正常基因片段控制合成多肽的过a-d表示4种基因突变.a丢失T/A 2020-11-13 …
果蝇约有10^4对基因,家丁每个记忆你的突变率是10^-5,一个在约有10^9的果蝇的果蝇约有10^ 2020-11-13 …
甲图表示果蝇某正常基因片段控制合成多肽的过程.a~d表示4种基因突变.a丢失T/A,b由T/A变为C 2020-11-29 …