(-1/2+(√3)i/2)^4-(1-i/√2)^4=?

题目详情

▼优质解答

答案和解析

原式=(cos2π/3+isin2π/3)^4-(cos7π/4-isin7π/4)^4
=(cos8π/3+isin8π/3)-(cos7π-isin7π)
=-1/2+i√3/2-(-1-0)
=1/2+i√3/2

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