x+y/2=z+x/3+y=z/4,x=2y+3z=60,求x,y,z的值三元一次方程组

Question

x+y/2=z+x/3+y=z/4,x=2y+3z=60,求x,y,z的值
三元一次方程组

Answer 1

x=2y+3z=60
60+y/2=z+20+y=z/4
即：60+y/2=z+20+y；z+20+y=z/4
y=80-2z
y=-3/4*z-20
即：z=80；y=-80