{x/3=y/2,y/4=z/5,x+y+z=120

Question

{x/3=y/2,y/4=z/5,x+y+z=120

Answer 1

第一个方程都乘3
得 X=3Y/2
第二个都乘5
得 Z=5Y/4
所以X+Y+Z=3Y/2+Y+5Y/4
=6Y/4+4Y/4+5Y/4
=15Y/4
=120
得 Y=32
望采纳\(^o^)/~