早教吧作业答案频道 -->英语-->
英语翻译1)Thesubstancedoesnotmeetthecriteriaforidentificationasacarcinogeninsituationswhereitcontainslessthan0.005%(w/w)benzo[a]pyrene(EINECSNo200-028-5)2)Thesubstancedoesnotmeetthecriteriaforidentificationas
题目详情
英语翻译
1) The substance does not meet the criteria for identification as a carcinogen in situations where it contains less than 0.005 % (w/w) benzo[a]pyrene (EINECS No 200-028-5)
2) The substance does not meet the criteria for identification as a carcinogen in situations where it contains less than 0.005 % (w/w) benzo[a]pyrene (EINECS No 200-028-5) and less than 0,1 % w/w benzene (EINECS No 200-753-7).]
3) The substance does not meet the criteria for identification as a mutagen in situations where it contains less than 0,1 % w/w benzene (EINECS No 200-753-7).]
1) The substance does not meet the criteria for identification as a carcinogen in situations where it contains less than 0.005 % (w/w) benzo[a]pyrene (EINECS No 200-028-5)
2) The substance does not meet the criteria for identification as a carcinogen in situations where it contains less than 0.005 % (w/w) benzo[a]pyrene (EINECS No 200-028-5) and less than 0,1 % w/w benzene (EINECS No 200-753-7).]
3) The substance does not meet the criteria for identification as a mutagen in situations where it contains less than 0,1 % w/w benzene (EINECS No 200-753-7).]
▼优质解答
答案和解析
1)物质不符合这些标准为识别作为一种致癌物质在这种情况下,它包含小于0.005 %(w / w)幷[j].EINECS 200-028-5芘(没有).
(2)物质不符合这些标准为识别作为一种致癌物质在这种情况下,它包含小于0.005 %(w / w)幷[j].没有200-028-5)芘(EINECS小于0和1 %瓦特/ w苯(EINECS没有200-753-7).)
三)物质不符合这些标准为识别作为一种诱导在这种情况下,它包含小于0、1 %瓦特/ w苯(EINECS没有200-753-7).)
(2)物质不符合这些标准为识别作为一种致癌物质在这种情况下,它包含小于0.005 %(w / w)幷[j].没有200-028-5)芘(EINECS小于0和1 %瓦特/ w苯(EINECS没有200-753-7).)
三)物质不符合这些标准为识别作为一种诱导在这种情况下,它包含小于0、1 %瓦特/ w苯(EINECS没有200-753-7).)
看了英语翻译1)Thesubsta...的网友还看了以下:
如果2/1△3=2/1×3/2×4/3,5/4△4=5/3×6/4×7/5×8/6那么5/2△5+ 2020-04-27 …
123312313213232111131+1+1+5+5+8+8+6+2+2+2+2+2+2+2 2020-05-17 …
1/1=11/2+2/2+1/2=21/3+2/3+3/3+2/3+1/3=31/4+2/4+3/ 2020-06-02 …
表达式Int(2.5)、ABS(2.5)、Int(-2.5)、ABS(-2.5)的运算结果分别是( 2020-06-09 …
计算(能简算的要简便)1:14.75-(7又11分之1-4.25)2:5又3分之1-2.75+4又 2020-07-18 …
已知2=2,2+5=7=1/2*(2+5)*2,2+5+8=15=1/2*(2+8)*3,2+5+ 2020-07-19 …
3.14*12*16+3.14*(12/2)2*23.14*5*20+3.14*(5/2)2*23 2020-07-19 …
(1)-22-(-1)3(2)4-5*(-1/2)3(3)(-10)2/5×(-2/5)(4)(- 2020-07-22 …
直接写出得数.0.5×4÷0.5×4=4.2-4.2×0.5=1.2÷4×1.2÷4=6.3+6.3 2020-11-19 …
甲、乙两组数据的平均数相等,但s甲2=0.026,s乙2=0.028,那么经过比较可得()A.甲比乙 2020-12-20 …