有一总体服从正态分布,其均值是60,标准差是12,从中随机选取一个容量为9的样本.标准误差是多少?Anormalpopulationhasameanof60andastandarddeviationof12.Youselectasampleof9torepresentthepopulation.Wh

Question

有一总体服从正态分布,其均值是60,标准差是12,从中随机选取一个容量为9的样本.标准误差是多少?
A normal population has a mean of 60 and a standard
deviation of 12.You select a sample of 9 to represent the population.What is
the standard error of the mean?
Answer
a.
4
b.
1.75
c.
12
d.
1.33

Answer 1

标准差=单体标准差/N^.5
=12/根号9
=12/3
=4
选a