若f(x)在x=1处有连续的一阶导数,且f'(1)=-2,求lim(x→0+)d(f(cosx^(1/2)))/dx=

Question

若f(x)在x=1处有连续的一阶导数,且f'(1)=-2,求lim(x→0+)d(f(cosx^(1/2)))/dx=___

Answer 1

=f‘(cosx^(1/2)) ·(-1/2)sinx^(1/2) / x^(1/2) | x→0+
=1