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计算：log2sinπ/8+log2cosπ/8=?
题目详情
计算：log2sinπ/8+log2cosπ/8=?
▼优质解答
答案和解析
log2(sinπ/8)+log2(cosπ/8)
=log2(sinπ/8 ·cosπ/8)
=log2[(sinπ/4)/2]
=log2(√2/4)
=log2√2 - log2(4)
=1/2 - 2
= -3/2
=log2(sinπ/8 ·cosπ/8)
=log2[(sinπ/4)/2]
=log2(√2/4)
=log2√2 - log2(4)
=1/2 - 2
= -3/2
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