早教吧作业答案频道 -->数学-->
2/3的-2次方+(1-根号2)的0次方-(33/8)的2/3次方+根号(3-π)平方
题目详情
2/3的-2次方+(1-根号2)的0次方 -(33/8)的2/3次方+根号(3-π)平方
▼优质解答
答案和解析
2/3的-2次方+(1-根号2)的0次方 -(33/8)的2/3次方+根号(3-π)平方
=(2/3)^(-2)+(1-√2)^0 -(33/8)^(2/3)+√(3-π)²
=9/4+1 - [(1089)^(1/3)]/4+π-3
=1/4+3 - [(1089)^(1/3)]/4+π-3
=1/4 - [(1089)^(1/3)]/4+π
={1 - [(1089)^(1/3)]}/4+π
≈2.32+π
=(2/3)^(-2)+(1-√2)^0 -(33/8)^(2/3)+√(3-π)²
=9/4+1 - [(1089)^(1/3)]/4+π-3
=1/4+3 - [(1089)^(1/3)]/4+π-3
=1/4 - [(1089)^(1/3)]/4+π
={1 - [(1089)^(1/3)]}/4+π
≈2.32+π
看了 2/3的-2次方+(1-根号...的网友还看了以下：