用韦达定理解根,但我算不对,3x^2+8x+4=0X1+X2=-8/3X1×X2=4/3这个怎么解两个根?

Question

用韦达定理解根,但我算不对,
3x^2+8x+4=0
X1+X2=-8/3
X1×X2=4/3
这个怎么解两个根?

Answer 1

（-8/3-x2）*x2=4/3
x2^2+8x2/3+4/3=0
3x2^2+8x2+4=0
(3x2+2)(x2+2)=0
x2=-2/3或x2=-2
x1=-2 x1=-2/3