用自然对数表示log1/6(a-b)A.ln(a-b)/ln6B.-ln(a-b)/ln6用自然对数表示log1/6(a-b)A.ln(a-b)/ln6B.-ln(a-b)/ln6C.ln6/ln(a-b)D.1/ln6

Question

用自然对数表示 log1/6(a-b) A.ln(a-b)/ln6 B.-ln(a-b)/ln6
用自然对数表示
log1/6(a-b)
A.ln(a-b)/ln6 B.-ln(a-b)/ln6
C.ln6/ln(a-b) D.1/ln 6

Answer 1

由换底公式：log(a)(b)=log(c)(b)/log(c)(a)
log(1/6)(a-b)
=ln(a-b)/ln(1/6)
=ln(a-b)/ln(6的-1次方)
=ln(a-b)/(-ln6)
=-ln(a-b)/ln6
所以选择B.