若x-1=（y+1）/2=(z-2)/3,则x^2+y^2+z^2可取得的最小值为

Question

若x-1=（y+1）/2=(z-2)/3,则x^2+y^2+z^2可取得的最小值为

Answer 1

设x-1=（y+1）/2=(z-2)/3=t,则 x=t+1,y=2t-1,z=3t+2
x^2+y^2+z^2=14t^2+10t+6
最小值为61/14