用5点法画出f(x)=根号2sin(2x-π/4）+1在(-π/2.π/2)的图像求解

Question

用5点法画出f(x)=根号2sin(2x-π/4）+1在(-π/2.π/2)的图像
求解

Answer 1

f(x)=[2sin(2x-π/4)]^(1/2)
sin(2x-π/4)>0, 2kπ